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determine the equation of a parabola with vertex at (-2,3) and fucos at (0,3), then graph the paragraph


Sagot :

Answer:

Equation of the Parabola

Step-by-step explanation:

To determine the equation of the parabola with a vertex at (−2,3)(−2,3) and a focus at (0,3)(0,3), follow these steps:

   Identify the Type of Parabola:

       Since the focus and the vertex have the same yy-coordinate (y=3y=3), the parabola opens horizontally.

   Find the Directrix:

       The directrix of a parabola is equidistant from the vertex as the focus but on the opposite side. Given the vertex (−2,3)(−2,3) and focus (0,3)(0,3), the distance between them is 2 units. Therefore, the directrix is at x=−2−2=−4x=−2−2=−4.

   Write the Standard Form of the Parabola:

       For a parabola opening horizontally, the standard form is (y−k)^2=4p(x−h)(y−k)^2=4p(x−h), where (h,k)(h,k) is the vertex and pp is the distance from the vertex to the focus (or the directrix).

       In this case:

           The vertex (h,k)=(−2,3)(h,k)=(−2,3)

           The distance p=2p=2 (from vertex to focus)

   Thus, the equation of the parabola is:

   (y−3)^2=4⋅2⋅(x+2)

   (y−3)^2=4⋅2⋅(x+2)

   (y−3)^2=8(x+2)

   (y−3)^2=8(x+2)

Graphing the Parabola

   Plot the Vertex: Mark the point (−2,3)(−2,3) on the graph.

   Plot the Focus: Mark the point (0,3)(0,3).

   Draw the Directrix: Draw a vertical line at x=−4x=−4.

   Sketch the Parabola:

       The parabola opens to the right since the focus is to the right of the vertex.

       The shape should be symmetrical around the line y=3y=3 and should curve towards the right from the vertex.

       Mark additional points on the parabola to help in sketching, such as points where x=−1x=−1 or x=−3x=−3 and find corresponding yy values using the equation (y−3)^2=8(x+2)(y−3)^2=8(x+2).

This will give you a complete picture of the parabola with the vertex, focus, and directrix clearly marked.

Answer:

Here is the equation of the parabola:

[tex](y - 3)^2 = 8(x + 2)[/tex]

Step-by-step explanation:

1. Identify the orientation of the parabola:

Since the vertex and focus share the same y-coordinate (3), the parabola opens horizontally. The focus is to the right of the vertex, indicating that the parabola opens to the right.

2. Determine the vertex and the focus-related properties:

[tex]Vertex \: \((h, k)\) = \((-2, 3)\)[/tex]

[tex]Focus \: \((h + p, k)\) = \((0, 3)\)[/tex]

The distance (p) (the distance from the vertex to the focus) is:

[tex]{h + p = 0 \implies -2 + p = 0 \implies p = 2}[/tex]

3. Equation of the parabola:

For a horizontally oriented parabola (opening right), the standard form is:

[tex] (y - k)^2 = 4p(x - h)[/tex]

Substituting (h = -2), (k = 3), and (p = 2):

[tex](y - 3)^2 = 4 \cdot 2 \cdot (x + 2)[/tex]

Simplifying:

[tex](y - 3)^2 = 8(x + 2)[/tex]

4. Graphing the Parabola:

To graph this parabola:

- Plot the vertex at (-2, 3).

- Plot the focus at (0, 3).

- Draw the directrix, which is a vertical line at (x = -4) (since the directrix is the same distance (p) on the opposite side of the vertex from the focus).

- Sketch the parabola ensuring it curves around the focus and opens towards the right.