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II. Problem Solving Directions: Read the given problem carefully and answer the questions below. The probabilities that a city councilor will discover violations of the public health code in a public market are given in the following table. Number of Violations(X) Probability P(X) 0 0.41 1 0.22 2 0.17 3 0.13 4 0.05 0.02 5 21. What is the probability that a city councilor will discover, at least, two violations of the public health code? 22. What is the probability that a city councilor will discover, at most, three violations of the public health code? 23. What is the probability that a city councilor will discover three violations of the public health code? 24. What is the probability that a city councilor will discover, at least three but less than five violations of the public health code? 25. What is the probability that a city councilor will discover, at least one but less than four violations of the public health code? 26-30. What is the mean of the probability distribution? (include solution and box your final answer) 31-35. What is the standard deviation of the probability distribution? (include solution and box your final answer) 36-40. What is the variance of the probability distribution? (include solution and box your final answer)​

Sagot :

Answer:

21. [tex]P_{X\geq 2} =P_{X=2} +P_{X=3} +P_{X=4} +P_{X=5} =0.17+0.13+0.05+0.02=0.37[/tex]

22.[tex]P_{X\leq 3} =P_{X=0} +P_{X=1} +P_{X=2} +P_{X=3} =0.41+0.22+0.17+0.13=0.93[/tex]

23. [tex]P_{X=3} =0.13[/tex]

24. [tex]P_{3\leq X < 5} =P_{X=3} +P_{X=4} =0.13+0.05=0.18[/tex]

25.[tex]P_{1\leq X < 4} =P_{X=1} +P_{X=2} +P_{X=3}=0.22+0.17+0.13=0.52[/tex]

26-30 μ = 0(0.41) + 1(0.22) + 2(0.17) + 3(0.13) + 4(0.05) + 5(0.02) = 1.25

I only answered until 30. 10pts is not enough for this problem set. As a bonus, I answered 26-30. Hopefully, you'll be able to answer the rest.