RueIfortunado21idn
Answered

Magtanong at makakuha ng eksaktong mga sagot sa IDNStudy.com. Ang aming platform ay idinisenyo upang magbigay ng mabilis at eksaktong sagot sa lahat ng iyong mga tanong.

What is the mole of 3.5 g AL(NO3)3?​

Sagot :

MrChrisidn

[tex]\underline{\underline{\large{\green{\cal{✒GIVEN:}}}}}[/tex]

[tex]\bullet \: \rm{3.5 g AL(NO3)3}[/tex]

[tex]\underline{\underline{\large{\green{\cal{REQUIRED:}}}}}[/tex]

Find the mole of 3.5 g AL(NO3)3.

[tex]\underline{\underline{\large{\green{\cal{SOLUTION:}}}}}[/tex]

The formula for calculating the [tex]\tt{\purple{mole \: of \: the \: compound}}[/tex] is expressed as:

[tex]\large{\boxed{\bm{\red{ mole= \dfrac{Mass}{Molar \: mass}}}}}[/tex]

Determine the molar mass of Al(NO3)3:

[tex]\tt{molar \: mass=27+3(14)+3(3×16)}[/tex]

[tex]\tt{molar \: mass=27+42+3(48)}[/tex]

[tex]\tt{molar \: mass=69+144}[/tex]

[tex]\tt{molar \: mass=213gmol^{−1}}[/tex]

Determine the required moles of Al(NO3)3, using the formula:

[tex]\tt{mole = \dfrac{3.5g}{213 {gmol}^{ - 1} } }[/tex]

[tex]\large{\tt{\purple{mole \approx 0.015 \: mol}}}[/tex]

Final Answer:

Hence, the mole of 3.5 g AL(NO3)3 [tex]\large{\rm{\purple{0.015 \: mol}}}[/tex]

NoahBadillaidn

MOLAR MASS

[tex]\normalsize{\blue{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad}}}[/tex]

What is the mole of 3.5 g AL(NO3)3?​

[tex]\\[/tex]

[tex]\rm{\underline{SOLUTION:}}[/tex]

To calculate how many moles are in 3.5 g of AL(NO3)3 (aluminum nitrate), first find the atomic masses of what aluminum nitrate is composed of. According to the periodic table:

  • Aluminum ≈ 27 g/mol
  • Nitrogen ≈ 14 g/mol
  • Oxygen ≈ 16 g/mol

[tex]\\[/tex]

In [tex]\sf{AL(NO_{3})_{3}}[/tex], there are:

  • 1 atom of aluminum
  • 3 atoms of nitrogen
  • 9 atoms of oxygen

[tex]\\[/tex]

Calculate the total molar mass of all three:

  • Aluminum: 1 atoms × 27 g/mol = 27 g/mol
  • Nitrogen: 3 atoms × 14 g/mol = 42 g/mol
  • Oxygen: 9 atoms × 16 g/mol = 144 g/mol

[tex]\\[/tex]

Calculate the number of moles using the formula:

Moles = mass/molar mass

  • [tex]\rm{Moles = \dfrac{mass}{molar \: mass} }[/tex]

  • [tex]\rm{Moles = \dfrac{3.5 \: g}{27 \: g/mol+42 \: g/mol+144 \: g/mol} }[/tex]

  • [tex]\rm{Moles = \dfrac{3.5 \: g}{213 \: g/mol} }[/tex]

  • [tex]\rm{Moles = \green{\underline{0.01643}}}[/tex]

[tex]\\[/tex]

Hence, there are 0.0164 moles in 3.5 g of [tex]\sf{AL(NO_{3})_{3}}[/tex].

[tex]\normalsize{\blue{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad}}}[/tex]

[tex]\large{\boxed{\tt{\blue{06/20/2024}}}}[/tex]

Salamat sa iyong pakikilahok. Huwag kalimutang magtanong at magbahagi ng iyong kaalaman. Ang iyong ambag ay napakahalaga sa aming komunidad. Salamat sa pagpili sa IDNStudy.com. Umaasa kami na makita ka ulit para sa mas maraming solusyon.