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Sagot :
Perimeter of a square:
Given: s = 7
P= 4s
= 4(7)
P= 28
Perimeter of a rectangle:
Given: l = 7 w=3
P= 2(l+w)
= 2(7+3)
= 2(10)
P= 20
Psquare - Prectangle
28 - 20 = 8 meters
Therefore the perimeter of square is longer than the perimeter of the rectangle by 8 meters. :)
Given: s = 7
P= 4s
= 4(7)
P= 28
Perimeter of a rectangle:
Given: l = 7 w=3
P= 2(l+w)
= 2(7+3)
= 2(10)
P= 20
Psquare - Prectangle
28 - 20 = 8 meters
Therefore the perimeter of square is longer than the perimeter of the rectangle by 8 meters. :)
Length(square)=7 m
P=4s
P=4(7 m)
P=28 m
Length(rectangle)=7 m
Width(rectangle)=3 m
P=2(l+w)
P=2(7+3)
P=2(10)
P=20 m
Therefore, the perimeter of the square is bigger than the perimeter of the rectangle, but only if that's the measurement. The perimeter of the square is 7 more than the perimeter of the rectangle.
Hope this helps =)
P=4s
P=4(7 m)
P=28 m
Length(rectangle)=7 m
Width(rectangle)=3 m
P=2(l+w)
P=2(7+3)
P=2(10)
P=20 m
Therefore, the perimeter of the square is bigger than the perimeter of the rectangle, but only if that's the measurement. The perimeter of the square is 7 more than the perimeter of the rectangle.
Hope this helps =)
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