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Sagot :
A regular pyramid means its base is a regular polygon (equal sides).
The base must have 5cm side since it's a square w/ area 25cm².
SA = [tex] A_{base} [/tex] + Lateral Area (4 AΔ)
150 = 25 + LA
LA = 125 = 4 AΔ
AΔ = 125/4
Recall that AΔ = 1/2 bh
[tex] \frac{125}{4} [/tex] = [tex] \frac{1}{2} [/tex] (5)(h)
h = 25/2 = 12.5cm
Therefore, the slant height is 12.5 cm.
The base must have 5cm side since it's a square w/ area 25cm².
SA = [tex] A_{base} [/tex] + Lateral Area (4 AΔ)
150 = 25 + LA
LA = 125 = 4 AΔ
AΔ = 125/4
Recall that AΔ = 1/2 bh
[tex] \frac{125}{4} [/tex] = [tex] \frac{1}{2} [/tex] (5)(h)
h = 25/2 = 12.5cm
Therefore, the slant height is 12.5 cm.
Surface Area=150cm²
Base Area=25cm²
From the formula of Area of Square=side²
We obtain side=5cm
Total Surface Area=Base Area + Lateral Surface Area
LSA= TSA- Base Area
=150cm²-25cm²
=125cm²
From the Formula of LSA=1/2Pl
where: P=Perimeter of Base
l=slant height
125cm²=1/2 (20cm)l
l=125cm²÷10cm
l=12.5cm
Base Area=25cm²
From the formula of Area of Square=side²
We obtain side=5cm
Total Surface Area=Base Area + Lateral Surface Area
LSA= TSA- Base Area
=150cm²-25cm²
=125cm²
From the Formula of LSA=1/2Pl
where: P=Perimeter of Base
l=slant height
125cm²=1/2 (20cm)l
l=125cm²÷10cm
l=12.5cm
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