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find the slant height of the regular square pyramid surface area is 150 cm squared and base area is 25 cm squared

Sagot :

A regular pyramid means its base is a regular polygon (equal sides).
The base must have 5cm side since it's a square w/ area 25cm².

SA = [tex] A_{base} [/tex] + Lateral Area (4 AΔ)

150 = 25 + LA
LA = 125 = 4 AΔ
AΔ = 125/4 

Recall that AΔ = 1/2 bh

[tex] \frac{125}{4} [/tex] = [tex] \frac{1}{2} [/tex] (5)(h)

h = 25/2 = 12.5cm

Therefore, the slant height is 12.5 cm.
Surface Area=150cm²
Base Area=25cm²

From the formula of Area of Square=side²
We obtain side=5cm

Total Surface Area=Base Area + Lateral Surface Area
LSA= TSA- Base Area
=150cm²-25cm²
=125cm²

From the Formula of LSA=1/2Pl
where: P=Perimeter of Base
           l=slant height

125cm²=1/2 (20cm)l
l=125cm²÷10cm
l=12.5cm