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Sagot :
Using Substitution Method:
-10x + 5y = 5 ----equation 1
x + y = 15 ----equation 2
--------------------
From equation 2
x + y = 15
x = 15 - y -----equation 2'
-------------------
Substitute equation 2' to equation 1
-10x + 5y = 5
-10(15-y) + 5y = 5
Distribute -10
-150 + 10y + 5y = 5
10y + 5y = 5 + 150
15y = 155
y = 31/3
or
y = 10.33
--------------------
Substitute y=31/3 to equation 2'
x = 15 - y
x = 15 - 31/3
x = 14/3
or
x = 4.67
--------------------
Using Elimination Method:
-10x + 5y = 5 ----equation 1
x + y = 15 ----equation 2
-------------------
Multiply equation 2 with 5
[x + y = 15] x5
5x + 5y = 75 ------equation 2'
-------------------
Subtract equation 1 from equation 2'
5x + 5y = 75
- -10x + 5y = 5
15x = 70
x = 14/3
-------------------
Multiply equation 2 with 10
[x + y = 15] x10
10x + 10y = 150 ----equation 3
-----------------
Add equations 3 and 1
10x + 10y = 150
+ -10x + 5y = 5
15y = 155
y = 31/3
-10x + 5y = 5 ----equation 1
x + y = 15 ----equation 2
--------------------
From equation 2
x + y = 15
x = 15 - y -----equation 2'
-------------------
Substitute equation 2' to equation 1
-10x + 5y = 5
-10(15-y) + 5y = 5
Distribute -10
-150 + 10y + 5y = 5
10y + 5y = 5 + 150
15y = 155
y = 31/3
or
y = 10.33
--------------------
Substitute y=31/3 to equation 2'
x = 15 - y
x = 15 - 31/3
x = 14/3
or
x = 4.67
--------------------
Using Elimination Method:
-10x + 5y = 5 ----equation 1
x + y = 15 ----equation 2
-------------------
Multiply equation 2 with 5
[x + y = 15] x5
5x + 5y = 75 ------equation 2'
-------------------
Subtract equation 1 from equation 2'
5x + 5y = 75
- -10x + 5y = 5
15x = 70
x = 14/3
-------------------
Multiply equation 2 with 10
[x + y = 15] x10
10x + 10y = 150 ----equation 3
-----------------
Add equations 3 and 1
10x + 10y = 150
+ -10x + 5y = 5
15y = 155
y = 31/3
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