We should do first the 3/8 +1/3 because it is on the parenthesis.
This is an addition problem, so we need to find two equivalent fractions that have the same denominators. Then we can add the numerators together.
List the multiples of each denominator until a common number is found.
Multiples of 8: 8, 16, 24
Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24
Now we know 24 is the least common denominator of 3/8 and 1/3.
We want the denominator of each fraction to be 24. But we can't change the denominator without changing the numerator too. To find the new numerator of each fraction, use this formula:
(Cd ÷ Dn) x Nm = Nn
Wherein
Cd = Common Denominator
Dn = Denominator
Nm = Numerator
Nn = New Numerator
(24 ÷ 8) × 3 = 9
Re-writing the first fraction, we get 9/24.
Plug in the values of the second fraction into the formula:
(24 ÷ 3) × 1 = 8
Re-writing the second fraction, we get 8/24.
[tex] \frac{9}{24}+ \frac{8}{24} = \frac{17}{24} [/tex]
So the answer will be 17/24, then let us multiply it by 4/5
Multiply the numerators across, and multiply the denominators across to get the product:
17/24 · 4/5 = 17(4) and 24(5)
Resulting to [tex] \frac{68}{120} [/tex]
We should reduce it to lowest terms.
68 / 2 = 34 / 2 = 17
120 / 2 = 60 / 2 = 30
So the answer is [tex] \frac{17}{30} [/tex]
