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A 0.00300 M solution of an acid is 12% ionised. Calculate the acid ionization constant Ka.​

Sagot :

Pathologistidn

Question:

A 0.00300 M solution of an acid is 12% ionized. Calculate the acid ionization constant Ka:

Answer:

Acid is  12 %  ionized. So, the degree of dissociation ( α ) is

[tex]a=\frac{12}{100}=0.12[/tex]

Now for the weak acid, the acid dissociation constant ( K a ) is being approximately given by:

[tex]Ka=Ca^{2}=0.00300 x(0.12)^2=4.32x10^-5[/tex]

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