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If two geometric means are inserted between 3 and -1029,
find the first geometric mean.​


Sagot :

Answer:

-21

Step-by-step explanation:

3,_,_,-1029

r=n-k√an(n should be small in size)

Over ak(k should be small in size)

r=4-1√a4(4 should be small in size)

Over a1(1 should be small in size))

r=3√-1029

Over 3

r=3√-343

r=-7(common difference)

Multiply to the first geometric extreme(given #)

3×-7=-21

-21×-7=147

147×-7=-1029