Answered

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marry is 6 year older then her younger sister. after 10 year sum of their ages will be 50 years. what are their present ages.

Sagot :

denote x as age of younger sister
marry x+6
after 10 years
the sum is 50
x+x+6=50
2x+6=50
2x=50-6
2x=54
divide by 2
x=27
x+x+6=50
27+27+6=50
27+34=50
50=50

so the present age is
marry is 34 years old
and younger sister is 27 years old