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Sagot :
[tex]2y-[7-(5y-4)]=6 \\\\2y-[7- 5y+4 ]=6 \\\\2y-[11- 5y ]=6\\\\2y- 11+ 5y =6\\ \\7y=6+11\\ \\7y=17\ \ / :7 \\ \\y=\frac{17}{7}=2\frac{3}{7}[/tex]
Here is my solution for your given problem
The given equation is 2y-[7-(5y-4)]=6
So you have to multiply the negative sign to the numbers within the close parenthesis 2y-[7-5y+4]=6
Then,add the like terms 2y-[-5y+11]=6
Multiply the negative sign to the enclosed numbers 2y+5y-11=6
Then,add the like terms and combine like terms 7y=6+11
Add the like terms 7y=17
Divide the following numbers to 7 to get the value of Y 7y/7=17/7
So the final answer is y=2.43
HOPING I HELPED YOU GUYS:D
--------DOMINI--------
The given equation is 2y-[7-(5y-4)]=6
So you have to multiply the negative sign to the numbers within the close parenthesis 2y-[7-5y+4]=6
Then,add the like terms 2y-[-5y+11]=6
Multiply the negative sign to the enclosed numbers 2y+5y-11=6
Then,add the like terms and combine like terms 7y=6+11
Add the like terms 7y=17
Divide the following numbers to 7 to get the value of Y 7y/7=17/7
So the final answer is y=2.43
HOPING I HELPED YOU GUYS:D
--------DOMINI--------
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