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Sagot :
Product means you are going to add two binomials.
Example of binomial:
(5 + 2x)
Example Problem: What is the product of the binomials (3 + x) and (2x + 3)?
Solution:
(3+x) + (2+4) Right the equation
=3 + x + x + 4 Remove the parenthesis
=x + 2x + 3 + 4 Add
=3x + 7
:)
Example of binomial:
(5 + 2x)
Example Problem: What is the product of the binomials (3 + x) and (2x + 3)?
Solution:
(3+x) + (2+4) Right the equation
=3 + x + x + 4 Remove the parenthesis
=x + 2x + 3 + 4 Add
=3x + 7
:)
Well, we're to use the FOIL method, or First, Outer, Inner, and Last Multiplying Method. Example:
[tex](x + 3)(x + 2) \\ x^{2} + 2x + 3x + 6 \\ x^{2} + 5x + 6[/tex]
Observe the pattern - we multiplied the first terms in two binomials, then we multiplied the outer terms, and you knew the rest.
There are some of the patterns used like:
- Sum/Difference
[tex](x + 2)(x - 2) \\ x^{2} - 4[/tex]
Notice that I only multiplied the first and last term, because we're to cancel the O and I in the method.
- Same Variable Multiplication
[tex](x + 4)(x + 6) \\ x^{2} + 10x + 24[/tex]
Notice that we had only to square the first term, add the two constants, and multiply the two constants also.
[tex](x + 3)(x + 2) \\ x^{2} + 2x + 3x + 6 \\ x^{2} + 5x + 6[/tex]
Observe the pattern - we multiplied the first terms in two binomials, then we multiplied the outer terms, and you knew the rest.
There are some of the patterns used like:
- Sum/Difference
[tex](x + 2)(x - 2) \\ x^{2} - 4[/tex]
Notice that I only multiplied the first and last term, because we're to cancel the O and I in the method.
- Same Variable Multiplication
[tex](x + 4)(x + 6) \\ x^{2} + 10x + 24[/tex]
Notice that we had only to square the first term, add the two constants, and multiply the two constants also.
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