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A 5000 kg truck is running at 60 km/h. if it were to be stop in 10 s by a constant speed. what is it negative acceleration?

Sagot :

Answer:

Its negative acceleration is - 1.67 m/[tex]s^2[/tex]

Explanation:

Acceleration is the rate of change of velocity of a moving body.

For the formula, we use:

[tex]V_{f} =V_{i} +at[/tex]

where

[tex]V_{f}[/tex]     is the final velocity, unit is in m/s

[tex]V_{i}[/tex]      is the initial velocity, unit is in m/s

[tex]a[/tex]       is the acceleration, unit is in m/[tex]s^2[/tex]

[tex]t[/tex]        is the time, unit is in seconds (s)

For the given information

[tex]m = 5000kg[/tex]

[tex]V_{i}=60km/h[/tex]

[tex]t=10s[/tex]

[tex]V_{f}=0[/tex]     since the truck went to a stop after 10 seconds

Conversion:

[tex]V_{i}= 60\frac{km}{h} x\frac{1000m}{1km} x\frac{1h}{3600s} =16.67\frac{m}{s}[/tex]

Solving the problem

Use the formula, then substitute the given information, we get:

[tex]V_{f} =V_{i} +at[/tex]

[tex]0=16.67m/s+a(10s)[/tex]

Transposing a(10s) to the left side of the equation, we have:

[tex]-a(10s)=16.67 m/s[/tex]

Divide both sides by - (10s), we have:

[tex]a=\frac{16.67m/s}{-(10s)}[/tex]

[tex]a=-1.67m/s^2[/tex]

Therefore, the negative acceleration is [tex]-1.67m/s^2[/tex].

To learn more about this topic, just click on the following links:

* How to compute acceleration

 https://brainly.ph/question/106259

* Law of acceleration

 https://brainly.ph/question/180967

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