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1/6(3×+10)> 5/12 (×-1) what is the answer pls assign it is my assignment

Sagot :

[tex] \frac{1}{6}(3x+10)\ \textgreater \ \frac{5}{12} (x-1)[/tex]

[tex] \frac{3}{6}x+ \frac{10}{6} \ \textgreater \ \frac{5}{12}x- \frac{5}{12} [/tex]

LCD: 12

[tex](12) \frac{3}{6}x+(12) \frac{10}{6} \ \textgreater \ (12) \frac{5}{12} -(12) \frac{5}{12} [/tex]

6x + 20 > 5x - 5

6x - 5x > -5 - 20

x > - 25

x = {x/x > -25}

x = { -24, -23, -22, ...}