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.Which of the following is a solution of the linear inequality: - 5 < 2x - 3 < 7?
a. -1
b.0
c.5
d. 10


Sagot :

-5 < 2x - 3 < 7 ---> -5 + 3 < 2x - 3 + 3 < 7 + 3 --> -2 < 2x < 10 --> (-2/2) < (2x/2) < (10/2) --> -1 < x < 5. The answer is B or 0 because 0 is included in the set (-1, 5).
[tex]- 5 < 2x - 3 < 7 \\ \\2x-3> -5 \ \ \wedge \ \ 2x-3 < 7 \ \ | \ add\ 2x\ to\ both\ sides \\ \\2x -3+3> -5+3 \ \ \wedge \ \ 2x-3+3 < 7 +3\\\\2x > -2 \ \ \wedge \ \ 2x <10 \ \ | \ divide \ both \ sides\ by\ 2 \\\\ x > -1 \ \ \wedge \ \ x < 5 \\\\Answer : \ b. \ 0 [/tex]
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