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find f(x) = 2(x-5) = -3x(x-1)
f(x) = ?


Sagot :

[tex]2(x-5) = -3x(x-1) \\2x-10 =-3x^2+3x \\3x^2-3x+2x-10=0 \\3x^2- x -10=0 \\ a=3, \ \ b=-1, \ \ c=-10\\\\\Delta =b^2-4ac = (-1)^2 -4\cdot3\cdot (-10) = 1+120 =121\\ \\x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{1-\sqrt{121}}{2\cdot 3 }=\frac{1-11}{6}=\frac{-10}{6}=-\frac{5}{3}[/tex]

[tex]x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{1+\sqrt{121}}{2\cdot 3 }=\frac{1+11}{6}=\frac{12}{6}=2 \\\\x= -\frac{5}{3} \\2(( -\frac{5}{3})-5)=-3 \cdot (-\frac{5}{3})( (-\frac{5}{3})-1)\\ \\ -\frac{10}{3} -10= 5\cdot ((-\frac{5}{3})-1)\\-\frac{10}{3} -\frac{30}{3}= 5\cdot ((-\frac{5}{3})-\frac{3}{3})\\-\frac{40}{3}=5\cdot (-\frac{8}{3}) \\ \\-\frac{40}{3}=-\frac{40}{3} [/tex]

[tex]x=2 \\2(2-5)=-3 \cdot 2( 2-1)\\ 2 \cdot (-3)=-3 \cdot 2 \cdot 1\\\\-6=-6[/tex]