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Sagot :
Answer:
To determine how many pounds of an alloy with 80% nickel must be mixed with an alloy that is 40% nickel to obtain 50 lbs of an alloy that is 50% nickel, we can set up the following equation:
Let x be the number of pounds of the 80% nickel alloy needed.
The amount of nickel in the 80% nickel alloy is 0.80x, and the amount of nickel in the 40% nickel alloy is 0.40(50 - x) since the total weight is 50 lbs.
The total amount of nickel in the final 50% nickel alloy is 0.50(50) = 25.
Therefore, we can write the equation:
0.80x + 0.40(50 - x) = 25
Solve for x:
0.80x + 20 - 0.40x = 25
0.40x = 5
x = 5 / 0.40
x = 12.5
So, you would need 12.5 lbs of the 80% nickel alloy and 37.5 lbs of the 40% nickel alloy to mix together to obtain 50 lbs of an alloy that is 50% nickel.
Step-by-step explanation:
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