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Sagot :
Answer:
To solve this problem, we need to find the value of the divisor.
Given information:
- When the original number is divided by the divisor, the remainder is 15.
- When twice the original number is divided by the same divisor, the remainder is 8.
Let's represent the original number as 'x' and the divisor as 'd'.
Step 1: Set up the equations based on the given information.
Original number divided by divisor leaves a remainder of 15:
x = d × q + 15, where q is the quotient.
Twice the original number divided by the same divisor leaves a remainder of 8:
2x = d × p + 8, where p is the quotient.
Step 2: Solve for the divisor 'd'.
From the first equation, we can express the original number 'x' in terms of the divisor 'd':
x = d × q + 15
Substituting this into the second equation:
2x = 2(d × q + 15) = d × (2q) + 30 = d × p + 8
Equating the coefficients of 'd':
2q = p
2q - p = 0
p = 2q
Substituting p = 2q into the second equation:
2(d × q + 15) = d × (2q) + 8
2dq + 30 = 2dq + 8
22 = 22
d = 22
Therefore, the value of the divisor is 22.
The correct answer is d) 22.
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