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2x - 6 = 4x², how can i find the value of x in this quadratic equation, i've been solving this since last week, instead of getting the answer i got sick​

Sagot :

To solve the quadratic equation 2x - 6 = 4x², we can follow these steps:

1. Subtract 2x from both sides:

2x - 6 - 2x = 4x² - 2x

-6 = 2x²

2. Divide both sides by 2:

-6/2 = 2x²/2

-3 = x²

3. Take the square root of both sides:

√(-3) = √(x²)

±√3i = x

Therefore, the solutions for x are:

x = ±√3i

The complex roots can be written in the form a + bi:

x = 1/4 (1 ± i√23)

The sum of the roots is:

1/4 (1 + i√23) + 1/4 (1 - i√23) = 1/2

The product of the roots is:

1/4 (1 + i√23) * 1/4 (1 - i√23) = 3/2

So, the solutions to the equation 2x - 6 = 4x² are:

x = 1/4 (1 - i√23)

x = 1/4 (1 + i√23)

where i is the imaginary unit (√(-1))[1].

I’m sorry to hear that you’ve been struggling with this quadratic equation! Let’s work through it together.

The given equation is: 2x−6=4x2

To find the value of (x), we can follow these steps:

1. Rearrange the equation to get all terms on one side:

[2x - 4x^2 - 6 = 0]

2. Combine like terms:

[4x^2 - 2x - 6 = 0]

3. Now, we can use the quadratic formula to find the solutions for (x):

[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}]

Here, (a = 4), (b = -2), and (c = -6).

Plugging in the values:

[x = \frac{-(-2) \pm \sqrt{(-2)^2 - 4 \cdot 4 \cdot (-6)}}{2 \cdot 4}]

Calculating the discriminant:

[b^2 - 4ac = (-2)^2 - 4 \cdot 4 \cdot (-6) = 4 + 96 = 100]

Taking the square root of the discriminant:

[\sqrt{100} = 10]

Now we have two possible solutions:

[x_1 = \frac{-(-2) + 10}{8} = \frac{12}{8} = 1.5]

[x_2 = \frac{-(-2) - 10}{8} = \frac{-12}{8} = -1.5]

So the solutions for the equation are (x = 1.5) and (x = -1.5). Feel free to double-check the calculations, and let me know if you have any other questions!

and I hope you got rid of that math sick !