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An 800kg car is going 15 m/s along a level high way. How much force is required to stop the car in a distance of 60 m?​

Sagot :

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Acceleration & Force

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An 800kg car is going 15 m/s along a level high way. How much force is required to stop the car in a distance of 60 m?

Given data:

  • Mass - 800 kg
  • Initial Velocity - 15 m/s
  • Final Velocity - 0 m/s (stop)
  • Distance - 60 m

Solution:

Step 1: First, let us find the acceleration by using the formula: A = vf² - vi² ÷ 2d

[tex]\sf A=vf² - vi² ÷ 2d[/tex]

[tex]\sf A = (0 \: m/s)^2-(15 \: m/s)^2 ÷ 2(60 \: m)[/tex]

[tex]\sf A = -225 \: m^2/s^2 ÷ 120 \: m[/tex]

[tex]\sf A = -1.8 \: m/s \: (decelerating)[/tex]

Step 2: Solve for force by using the formula: F = ma

[tex]\sf F=ma[/tex]

[tex]\sf F = (800 \: kg)(-1.8 \: m/s)[/tex]

[tex]\sf F = 798.2 \: kg.m^2/s^2[/tex]

[tex]\sf F = \boxed{\sf 798.2 \: N}[/tex]

Answer:

Therefore, the force needed to stop the car is 798.2 N.

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