SOLUTION:
Step 1: List the given values.
[tex]\begin{aligned} & V_1 = \text{2 L} \\ & T_1 = 27^{\circ}\text{C} = \text{300 K} \\ & T_2 = 227^{\circ}\text{C} = \text{500 K} \end{aligned}[/tex]
Step 2: Calculate the final volume by using Charles' law.
[tex]\begin{aligned} \frac{V_1}{T_1} & = \frac{V_2}{T_2} \\ V_2T_1 & = V_1T_2 \\ \frac{V_2T_1}{T_1} & = \frac{V_1T_2}{T_1} \\ V_2 & = \frac{V_1T_2}{T_1} \\ & = \frac{(\text{2 L})(\text{500 K})}{\text{300 K}} \\ & = \text{3.3333 L} \\ & \approx \boxed{\text{3.33 L}} \end{aligned}[/tex]
Hence, the volume of the gas will be 3.33 L if the temperature is increased to 227°C.
[tex]\\[/tex]
#CarryOnLearning
