Answered

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1. A 4.45 mol sample of gas has a volume of 5.85 L. If 8.55 moles of the same sample are added without changing the temperature and pressure, what will be the new volume?

a. 18.1 L

b. 17.1 L

c. 15.1 L

d. 16.1 L

Sagot :

SOLUTION:

Step 1: List the given values.

[tex]\begin{aligned} & V_1 = \text{5.85 L} \\ & n_1 = \text{4.45 mol} \\ & n_2 = n_1 + \text{8.55 mol} = \text{4.45 mol + 8.55 mol = 13.00 mol} \end{aligned}[/tex]

Step 2: Calculate the final volume of the gas by using Avogadro's law.

[tex]\begin{aligned} V_2 & = \frac{V_1n_2}{n_1} \\ & = \frac{(\text{5.85 L})(\text{13.00 mol})}{\text{4.45 mol}} \\ & = \boxed{\text{17.1 L}} \end{aligned}[/tex]

Hence, the answer is b. 17.1 L.

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Note: Kindly swipe the screen to the left to see the continuation on the right side.

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