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if a rock is throw into the air at 30 degree angle with a velocity of 20m/s, what is the maximum height reached by the rock?​

Sagot :

LESSON motion

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Answer:

  • 2.387

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Step-by-step explanation:

GIVEN:

  • if a rock is throw into the air at 30 degree angle with a velocity of 20m/s, what is the maximum height reached by the rock?

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FIND:

  • DY or height

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FORMULA:

  • For time = [tex] t = \frac{(vo)(sin)}{g}[/tex]
  • For dy = [tex] dy = vo \: sin \: t \: - \: \frac{1}{2} \: g \: t²[/tex]

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SOLVE:

  • for time

[tex] t = \frac{(vo)(sin)}{g}[/tex]

[tex] t = \frac{(20m/s)(0.342)}{9.8m/s}[/tex]

[tex] t = \frac{6.84}{9.8m/s}[/tex]

[tex] t = 0.697 \: s [/tex]

  • for dy or height

[tex] dy = vo \: sin \: t \: - \: \frac{1}{2} \: g \: t²[/tex]

[tex] dy = (20m/s)(0.342)(0.697) - \frac{1}{2}(9.8m/s)(0.697)²[/tex]

[tex] dy = 4.767 - 2.380 [/tex]

[tex] dy = 2.387[/tex]

ANSWER:

  • There fore the height of travel of the rock is 2.387

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