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Find thw 25th term of thee aritmetic sequence 3, 7, 11, 15, 19...

Sagot :

the 25th is 99 or ninety nine
Arithmetic sequence:
[tex]a _{n} = a _{1} + (n-1)(d) [/tex]

Where:
[tex]n [/tex] = number of terms (nth term) ⇒   25
[tex]a _{n} [/tex] = last term in the sequence   ⇒  unknown
[tex]a _{1} [/tex] = first term in the sequence   ⇒  3
d = common difference (difference between any two consecutive terms in the sequence)
d = 4

Solution:
[tex]a _{25} [/tex] = 3 + (25-1) (4)
[tex]a _{25} [/tex] = 3 + (24)(4)
[tex]a _{25} [/tex] = 3 + 96
[tex]a _{25} [/tex] = 99

ANSWER: The 25th term in the sequence is 99.