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Sagot :
1. sol. 5x + 3( x+2) = 62
5x + 3x +6 = 62
8x = 62 - 6
8x = 56 or x= 7
Therfore first odd integer is 5( 7) = 35
2. Sol. Brother - x
Carol - 5x
5x + 2 = 3 ( x+2)
5x + 2 = 3x + 6
5x - 3x = 6- 2
2x = 4 or x = 2
Therefore : Carol is now 10 yrs. old
5x + 3x +6 = 62
8x = 62 - 6
8x = 56 or x= 7
Therfore first odd integer is 5( 7) = 35
2. Sol. Brother - x
Carol - 5x
5x + 2 = 3 ( x+2)
5x + 2 = 3x + 6
5x - 3x = 6- 2
2x = 4 or x = 2
Therefore : Carol is now 10 yrs. old
1.) First odd integer: x
Second odd integer: x + 2
Equation:
5x + 3(x+2) = 62
5x + 3x + 6 = 62
8x = 62 - 6
8x = 56
8x/8 = 56/8
x = 7
ANSWER: The first odd integer is 7.
The second odd integer is:
x + 2 = (7) + 2 = 9
Check:
5 (7) + 3 (9) = 62
35 + 3(9) = 62
35 + 27 = 62
62 = 62
2) Present ages:
Carol's brother: x
Carol: 5x
Ages in two years:
Carol's brother: x + 2
Carol: 5x + 2
Equation:
5x + 2 = 3(x + 2)
5x + 2 = 3x + 6
5x - 3x = 6 - 2
2x = 4
2x/2 = 4/2
x = 2
Present ages: (Substitute 2 for x)
Carol's brother: x = 2 years old
Carol: 5x = 5(2) = 10 years old
ANSWER: Carol is now 10 years old.
Ages in 2 years:
Carol's brother: 2 + 2 = 4 years old
Carol: 10 + 2 = 12 years old
In two years, Carol will be three times as old as her brother.
12 = 3 (4)
12 = 12
Second odd integer: x + 2
Equation:
5x + 3(x+2) = 62
5x + 3x + 6 = 62
8x = 62 - 6
8x = 56
8x/8 = 56/8
x = 7
ANSWER: The first odd integer is 7.
The second odd integer is:
x + 2 = (7) + 2 = 9
Check:
5 (7) + 3 (9) = 62
35 + 3(9) = 62
35 + 27 = 62
62 = 62
2) Present ages:
Carol's brother: x
Carol: 5x
Ages in two years:
Carol's brother: x + 2
Carol: 5x + 2
Equation:
5x + 2 = 3(x + 2)
5x + 2 = 3x + 6
5x - 3x = 6 - 2
2x = 4
2x/2 = 4/2
x = 2
Present ages: (Substitute 2 for x)
Carol's brother: x = 2 years old
Carol: 5x = 5(2) = 10 years old
ANSWER: Carol is now 10 years old.
Ages in 2 years:
Carol's brother: 2 + 2 = 4 years old
Carol: 10 + 2 = 12 years old
In two years, Carol will be three times as old as her brother.
12 = 3 (4)
12 = 12
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