Answer:
- 17622.5 m²
- 1962.5 cm², 537.5 cm²
Step-by-step explanation:
Solution for #1
Given the radius of the park which is 75 m, we can solve for the area by using the formula: A = πr², where A stands for the area and r stands for "radius".
Note: π (pi) is usually estimated to the value of 3.14. (π ≈ 3.14)
A = πr²
A = (3.14)(75²)
A = (3.14)(5625)
A = 17622.5
Therefore, the area of the circle is 17622.5 m².
Solution for #2
Since a square has equal sides (given the side length of 50 cm), we can conclude that 50 cm is the biggest length of diameter which can form the biggest circle in the square cartolina.
Note: Diameter is twice the length of radius. Thus, the radius would be 25 cm.
When solving for the area of a circle, once again, we can use the formula: A = πr², where A stands for the area and r stands for "radius", with the given length of radius 25 cm.
A = (3.14)(25²)
A = (3.14)(2500)
A = 7850
Therefore, the largest possible area of the circle we can form in the square cartolina with a length of 50cm is 1962.5 cm².
We can solve for the area of the material wasted by getting the difference between the whole square cartolina and the area of the circle (1962.5 cm²). When solving for the area of the square (cartolina), we can use the formula: A = s², where s stands for "side" and A stands for the area.
A = s²
A = 50²
A = 2500
Thus, the area of the whole square cartolina is 2500 cm².
As what I've told earlier, we can solve for the area of the material wasted by getting the difference between the whole square cartolina (2500 cm²) and the area of the circle (1962.5 cm²).
2500 cm² - 1962.5 cm² = 537.5 cm²
Therefore, the area of the wasted material is 537.5 cm².
