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Sagot :
Uncut piece of cardboard:
Width: x inches
Length: 2x inches
Piece of cardboard with four cut-out corners:
Subtract 2 × 2 inches from length and width to compute for the volume of the uncovered box formed.
Width: x - 4 inches
Length: 2x - 4 inches
Height: 2 inches
Volume: 140 cubic inches
Equation:
Length × Width × Height = Volume
(2x-4) (x-4) (2) = 140
(2x² - 8x - 4x + 16) (2) = 140
(2x² - 12x + 16) (2) = 140
4x² - 24x + 32 = 140
Quadratic equation, ax² + bc + c = 0
4x² - 24x + 32 - 140 = 0
4x² - 24x - 108 = 0
Solve by factoring:
4(x² - 6x - 27) = 0
x - 9 = 0 x + 3 = 0
x = 9 x = -3
Choose the positive root, x = 9.
Dimensions of the uncut piece of board:
Width: x = 9 inches
Length: 2x = 2(9) = 18 inches
The dimensions are 9 inches and 18 inches.
Check:
(18 - 4) (9 - 4) (2) = 140
(14) (5) (2) = 140
140 = 140
Width: x inches
Length: 2x inches
Piece of cardboard with four cut-out corners:
Subtract 2 × 2 inches from length and width to compute for the volume of the uncovered box formed.
Width: x - 4 inches
Length: 2x - 4 inches
Height: 2 inches
Volume: 140 cubic inches
Equation:
Length × Width × Height = Volume
(2x-4) (x-4) (2) = 140
(2x² - 8x - 4x + 16) (2) = 140
(2x² - 12x + 16) (2) = 140
4x² - 24x + 32 = 140
Quadratic equation, ax² + bc + c = 0
4x² - 24x + 32 - 140 = 0
4x² - 24x - 108 = 0
Solve by factoring:
4(x² - 6x - 27) = 0
x - 9 = 0 x + 3 = 0
x = 9 x = -3
Choose the positive root, x = 9.
Dimensions of the uncut piece of board:
Width: x = 9 inches
Length: 2x = 2(9) = 18 inches
The dimensions are 9 inches and 18 inches.
Check:
(18 - 4) (9 - 4) (2) = 140
(14) (5) (2) = 140
140 = 140
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