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Six rectangles each with a common base width of 2 have lengths of 1,4,9,16,25, and 36. What is the sum of the areas of the six rectangles?

Sagot :

So first, we have to get the area of each rectangle, in which the formula is A = (l)(w), where l is the length and w is the width.

Rectangle having the length of 1: A = (1)(2) = 2
Rectangle having the length of 4: A = (4)(2) = 8
Rectangle having the length of 9: A = (9)(2) = 18
Rectangle having the length of 16: A = (16)(2) = 32
Rectangle having the length of 25: A = (25)(2) = 50
Rectangle having the length of 36: A = (36)(2) = 72

2+8+18+32+50+72 = 182

Therefore, the answer is 182.




- D.E.