YellowTulipidn
Answered

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Ed can do a job in 4 days. When Ed and Maymay work together it would take them
2 and 1/3 days. How long would the job take Maymay to do the job alone?

Include the labels for each variable used and the original fraction and the equation, in other words, THE COMPLETE SOLUTION.

Sagot :

Representation:
Let x be the number of days it takes Maymay to do the job alone.

Ed =  1 
         4 days

Maymay =       1     
                    x days

Working together =       1    
                              2 [tex] \frac{1}{3} } [/tex] days

                          =     1  
                               [tex] \frac{7}{2} [/tex]  days

                          =   (1) (7/2)  ⇒  2/7  days

Equation:
  1/4  +  1/x  =  2/7

LCD:  (4)(7)(x)

Solution:
1 (4)(7)(x)  +  1 (4)(7)(x)  =  2 (4)(7)(x)
    4                         x               7

7x + 28 = 8x

7x - 8x = -28
-x = -28
-x/-1 = -28/-1
x = 28

It would take Maymay 28 days to do the job alone.

Check:

1/4 + 1/28 = 2/7

LCD: 28

7/28 + 1/28 = 8/28

8/28 = 8/28

2/7 = 2/7