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In how many ways you can place 4 red balls, 3 yellow balls, 6 black balls, 2 blue balls and 1 orange in a row?​​

Sagot :

In terms of probability, there are exactly 144 ways.

We can do it by using the tree diagram or listing. However, it is too many and would take way too long, the best answer is to multiply all the variations in the statement; 4x3x6x2x1=144.

Each one can place two balls and two balls can place up as much as how many there are.

And if you are furthermore being problemed about these types of questions, just do multiplication to those choices.

Gimme Brainliest please