[tex]\tt{\huge{\red{Solution:}}}[/tex]
Step 1: List the given values
[tex]\begin{aligned} P_1 & = \text{3.00 atm} \\ V_1 & = \text{2.50 L} \\ P_2 & = \text{1.00 atm} \end{aligned}[/tex]
Final Step: Calculate the final volume using Boyle's law.
[tex]\begin{aligned} V_2 & = \frac{P_1V_1}{P_2} \\ & = \frac{(\text{3.00 atm})(\text{2.50 L})}{\text{1.00 atm}} \\ & = \boxed{\text{7.50 L}} \end{aligned}[/tex]
Hence, the final volume of the gas is 7.50 L.
[tex]\\[/tex]
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