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Mr. Sta. Maria is 5 years older than his wife. 5 years ago, his age was 4/3 her age. What willl be their ages 8 years from now?

Sagot :

Present Ages:
Mrs. Sta. Maria: x
Mr. Sta. Maria:  x + 5

Their ages 5 years ago:
Mrs. Sta. Maria: x-5
Mr. Sta. Maria:  (x+ 5) -5  or x

Comparison 5 years ago: Mr. Sta. Maria's age was 4/3 of his wife's age.
x = 4/3 (x-5)
x = 4x/3 - 20

LCD: 3; Multiply each term by 3.

(3)x = (3) (4x/3) - 3(20)
3x = 4x - 60
-4x + 3x = -60
-1(-x = -60)-1

x = 60

Present ages:
Mrs. Sta. Maria; x = 60 years old
Mr. Sta. Maria: x + 5 ⇒ 60 + 5 = 65 years old

Their ages in 8 years (Plus 8):
Mrs. Sta. Maria: 60 + 8 = 68 years old
Mr. Sta. Maria: 65 + 8= 73 years old

In 8 years, Mr. Sta. Maria will be 73 years old and his wife will be 68 years. old.