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What is the kinetic energy of a proton (proper mass is m0 = 1.67 x 10^-27 kg) travelling at 40 % of the speed of light?

Sagot :

Answer:

The total energy can be calculated using the relativistic form of the mass-energy equivalence formula, E=mc2

The relativistic form is as below:

E=γ×m×c2

Where γ is the Lorentz factor arising from Lorentz transformations, and is equal to:

γ=11−v2c2√

Here, v is the velocity which in this case is 0.6c

Therefore, γ becomes

γ=11−(0.6×c)2c2√

γ=11−0.36×c2c2√

γ=11−0.36√

γ=10.64√

γ=10.8

γ=1.25

Therefore, the total energy, E is now:

E=1.25×1.67×10−27×2997924582

E=1.876151435613099938×10−10J

E=1.172GeV

correct me if Im wrong