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if a:b=3:5, a:c=4:7 and c is 63, what is the sum of a,b and c

Sagot :

[tex] \frac{a}{c} = \frac{4}{7} [/tex]
c = 63

[tex] \frac{4}{7} = \frac{a}{63} [/tex]

[tex] \frac{4}{7} = \frac{a}{63} [/tex]
7a = (4) (63)
[tex] \frac{7a}{7} = \frac{252}{7} [/tex]

a = 36

[tex] \frac{a}{b} = \frac{3}{5} [/tex]; a = 36
[tex] \frac{3}{5} = \frac{36}{b} [/tex]

3b = (5)(36)
[tex] \frac{3b}{3} = \frac{180}{3} [/tex]

b = 60

The sum of a, b, and c,  where a=36;  b=60;  c=63

36 + 60 + 63 = 159