Tuklasin ang mundo ng kaalaman at mga sagot mula sa komunidad sa IDNStudy.com. Ang aming mga eksperto ay handang magbigay ng malalim na sagot at praktikal na solusyon sa lahat ng iyong mga tanong.
Answer:
LETTER D (none)
Step-by-step explanation:
√2-x = x-2
(√2-x)² = (x-)²
2-x = x²-4x+4
0 = x²-4x+x+4-2
0 = x²-3x-2
0 = (x-2)(x-1)
0 = x-2 and 0 = x-1
2 = x and 1 = x
Therefore , the roots are 1 and 2
To check the extraneous root , we will substitute the value of x which are 1 and 2
For x = 1
√2-x = x-2
√2-1 = 1-2
√1 = -1
±1 = -1 , it is true
For x = 2
√2-x = x-2
√2-2 = 2-2
√0 = 0
0 = 0 , it is true
Now , we conclude that there are no extraneous root for the solutions