IDNStudy.com, ang iyong mapagkukunan para sa malinaw at maaasahang mga sagot. Makakuha ng mabilis at eksaktong sagot sa iyong mga tanong mula sa aming mga eksperto na laging handang tumulong.

15. Whai ta the extraneous root of √ 2-x=x-2
a .1
b.2
c .3
d.none


Sagot :

Answer:

LETTER D (none)

Step-by-step explanation:

√2-x = x-2

(√2-x)² = (x-)²

2-x = x²-4x+4

0 = x²-4x+x+4-2

0 = x²-3x-2

0 = (x-2)(x-1)

0 = x-2 and 0 = x-1

2 = x and 1 = x

Therefore , the roots are 1 and 2

To check the extraneous root , we will substitute the value of x which are 1 and 2

For x = 1

√2-x = x-2

√2-1 = 1-2

√1 = -1

±1 = -1 , it is true

For x = 2

√2-x = x-2

√2-2 = 2-2

√0 = 0

0 = 0 , it is true

Now , we conclude that there are no extraneous root for the solutions