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find the length and the width of the rectangle​

Find The Length And The Width Of The Rectangle class=

Sagot :

[tex]\large\underline\mathcal{SOLUTION:}[/tex]

Given rectangle, with:

  • Perimeter, P = 30 units
  • length, l = 3 + √x units
  • width, w = √x units

then,

  • P = 2 (l + w)
  • 30 = 2 (3 + √x + √x)
  • 30 = 2 (3 + 2√x)
  • 30 = 6 + 4√x
  • 4√x = 30 - 6
  • √x = 24/4
  • (√x)² = (6)²
  • x = 36

We get, Solve for length:

  • l = 3 +√x
  • l = 3 + √36
  • l = 3 + 6
  • l = [tex]{\boxed{\green{\sf{9\:units }}}}[/tex]

Solve for width,

  • w = √x
  • w = √36
  • w = [tex]{\boxed{\green{\sf{6\:units }}}}[/tex]

[tex]\large\underline\mathcal{ANSWER:}[/tex]

  • Therefore, the length of the rectangle is 9 units and the width is 6 units.

hope this helps

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