Answer:
D. f(x) = 2x^3 + x^2 - 4x - 1
SSN26 Explanation
Given:
f(x) = (x+1) (x+1) (2x-3)
Solution:
Solving it from left to right.
f(x) = (x+1) (x+1) (2x-3)
f(x) = (x^2 + x + x + 1) (2x-3)
f(x) = (x^2 + 2x + 1) (2x-3)
f(x) = (2x)(x^2 + 2x + 1) - (3)(x^2 + 2x + 1)
f(x) = (2x^3 + 4x^2 +2x) - (3x^2 +6x +1)
f(x) = (2x^3 + 4x^2 +2x) - (3x^2 +6x +1)
f(x) = 2x^3 + x^2 - 4x - 1
*The standard form of an equation is when the highest
degree term is placed first followed by the lower
degree. In this sample:
2x^3 = 3rd degree
x^2 = 2nd degree
- 4x = 1st degree
- 1 = 0 degree
explanation: -1 (x^0)
-1 (1)
-1
*any non zero number raised to zero
will be equal to 1
