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Answer:
Given:
4 kg of soya beans, and (x) stands for cost each kg
3 kg of brown sugar, and (y) stands for cost each kg
a kilogram of brown sugar is Php 45.00
paid of not more than Php 463.00.
Solution
Total cost ≥ (Cost of soya beans)(kg of soya beans) + (cost of brown sugar)(kg of brown sugar)
463 ≥ (x)(4) + 45(3)
463 ≥ 4x + 135
463 - 135 ≥ 4x
328 ≥ 4x
4x ≥ 328/4
x ≥ 82
Answer: Php. 82.00