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Which one of the following lines is parallel to the line whose equation is 4x+2y-6=0?

6x+3y-1=0
3x+6y+1=0
6x-3y+1=0
3x-6y-1=0


Sagot :

We multiply (4x + 2y - 6 = 0) by (1/2): 2x + y - 3 = 0. We multiply by 3, we get: 6x + 3y - 9 = 0. So, the answer is a. 6x + 3y - 1 = 0. (Keep in mind that in parallel lines, the value for c is not necessarily equal to ensure parallel equations, you only need similar a and b values (coefficients of x and y).