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the potential energy of 40 kg cannonball is 14000 j how high was the canyon ball to have this much potential energy

maayus nasagut po with solution ​


Sagot :

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The height or position of an object is given by

[tex]\boxed{h = \frac{PE}{mg}}[/tex]

where:

h = height

PE = potential energy

g = acceleration due to gravity = 9.8 m/s²

h = height

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for the height

[tex]h = \dfrac{PE}{mg}[/tex]

[tex]h = \dfrac{\text{14,000 J}}{(\text{40 kg})(\text{9.8 m/}\text{s}^{2})}[/tex]

[tex]\boxed{h = \text{35.71 m}}[/tex]

Therefore, the cannon ball is at the height of 35.71 m.

[tex]\\[/tex]

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