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A 12 gram bullet is accelerated from rest to a speed of 700 m/s as it travels 20 cm in a gun barrel. Assuming the acceleration to be constant, how large was the accelerating force?

Sagot :

Answer:

Mass of the bullet=12g=0.012kg

Initial velocity=0m/s

Final velocity=700m/s

Distance (s)=20cm=0.2m

Using the third equation of motion i.e. v^2-u^2=2as

We get (700)^2-(0)^2=2*a*0.2

490000=0.4a

a=490000/0.4=1225000m/s^2

Now force is mass*acceleration

Acceleration=1225000m/s^2

So force= 0.012*1225000= 14700 Newton or 14700N