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when invested at an annual interest rate of 10% an amount earned php 14000 of simple interest in the three years and 6 months how much money was originally invest
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Sagot :

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Answer:

Ann invested $12,000 in two bank accounts.  One of the accounts pays 6% annual interest, and the other account pays 5% annual interest.  If the combined interest earned in both accounts after a year was $700, how much money was invested in each account?

What are we trying to find in this problem?

We want to know the amount of money invested in each account-- in other words, we want to know the amount invested in the 6% account and the amount invested in the 5% account.  Each of the things we are trying to find will be represented by a variable:

x = amount invested at 6%

y = amount invested at 5%

Since we have two variables to solve for, we will need to find a system of two equations to solve.

How do we find the two equations we need?

We are given two numbers in the problem:

$12,000 = total money invested in both accounts

$700 = total interest earned in both accounts

Let's start with the $12,000.  Ann wants to split this money into two parts.  We have chosen to call the two parts x and y.  Since these two parts must total to $12,000

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