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1)find the geometric sequence whose 5th term is 3 125 and whose common ratio is -5. show the

complete solution​


Sagot :

Answer:

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View image Sarsalejoneil20
View image Sarsalejoneil20

Solution:

First, determine the 1st term

[tex]A_n=A_1(r)^{n-1}\\\\3,125=A_1(-5)^{5-1}\\\\3,125=A_1(-5)^4\\\\3,125=A_1(625)\\\\\frac{3,125}{625}=A_1\\\\A_1=5[/tex]

Therefore:

[tex]A_1=5\\A_2=5(-5)=-25\\A_3=-25(-5)=125\\A_4=125(-5)=-625\\A_5=-625(-5)=3,125\\A_6=3125(-5)=-15,625\\[/tex]

and so on...

[correct me if I'm wrong]