Petermanuelzamoraidn
Answered

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There are two square lots in a subdivision. The side length of one lot is 2 meters less than the side length of the other. The area of the larger lot is 44 square meters greater than that of the smaller. Find the dimensions of each lot.

Sagot :

Shinalcantaraidn

let 'a' be the length of one side of the larger square

let 'b' be the length of one side of the smaller square

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since we are given that the side length of one lot is 2 meters less than the other then we can have the equation as

b = a - 2    ------equation 1

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Given that the area of the larger square is 44 square meters greater than that of the smaller then we'll have

a² - b² = 44    ----equation 2

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substitute equation 1 to equation 2

a² - (a-2)² = 44

simplify

a² - (a² - 4a + 4) = 44

a² - a² + 4a - 4 = 44

4a = 44 + 4

4a = 48

a = 12 m

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substitute the value of 'a' to equation 1

b = a - 2

b = 12 - 2

b = 10m

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therefore we can say that the smaller square measures 10 x 10 m and the larger square measures 12 x 12 m

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