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how much kinetic energy is present in a 350 kg object with a constant speed of 400 m/s​

Sagot :

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The kinetic energy of a moving object is given by

[tex]\boxed{KE = \frac{1}{2}mv^{2}}[/tex]

where:

KE = kinetic energy

m = mass

v = speed

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for KE

[tex]KE = \dfrac{1}{2}mv^{2}[/tex]

[tex]KE = \dfrac{1}{2}(\text{350 kg})(\text{400 m/s})^{2}[/tex]

[tex]\boxed{KE = 2.8 \times 10^{7} \: \text{J}}[/tex]

Therefore, the kinetic energy is 2.8 × 10⁷ J.

[tex]\\[/tex]

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