Ynnasolares54idn
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age. 21 years old Learning Task 10 I. Direction: Solve each problem. Write your answers on a sheet of paper. 1. Write an algebraic equation for the cost of 21 liters of gasoline, if x pesos per liter is P2,092. 2. Samantha is y years old now. Write an algebraic equation for Samantha's age if her age 5 years from now is 17. 3. Leo is g centimeter tall. Ralph's height is 4 less than thrice the height of Leo. Write an algebraic equation showing the difference of Leo's height when subtracted from Ralph's height will result to 240 centimeters. 4. In three years, the price of a new model of an S6-mobile phone will be six more than twice its current price. If the projected price of the new S6 phone is P40,000, what algebraic equation to express its current price? 5. Romar is twice as old as Mavic. Jaypee is 8 years older than Romar. Write an algebraic equation showing that twice the sum of Romar and Mavic ages will result to Jaypee's age.​

Sagot :

AnggeRance03idn

Answer:

1. 21x= 2092

Let x be the cost per liter

21x= 43 932

[tex] \frac{21x}{21} = \frac{43932}{21} \\ x = 2092 [/tex]

2. y + 5 = 17

[tex]y + 5 = 17 \\ y = 17 - 5 \\ y = 12[/tex]

3. ( 3g - 4) - g = 240

[tex]leo= g \\ ralph = 3g - 4 \\ (3g - 4) - g = 240 \\ 2g - 4 = 240 \\ 2g = 244 \\ g = 122 \\ leo= 122 \\ ralph= 362 \\ [/tex]

4. 2x + 6=40 000

[tex]let \: x \\ 40000 = 2x + 6 \\ 40000 - 6 = 2x \\ 39994 = 2x \\ x = 19997 \\ 2 \times + 6 = 40000[/tex]

5. 2(2x+x)=2x+8

[tex]let \: say \: \\ mavic \: age = x \\ romar = 2x \\ jaypee = 2x + 8 \\ 6x = 2x + 8 \\ 4x = 8 \\ x = 2 \\ mavic = 2 \\ romar = 4 \\ jaypee = 12[/tex]

Hope it helps

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