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A 1 kg pistol, initially at rest, shoots a bullet with a mass of 2.5g. After firing, the bullet travels at a speed of 150m/s. What will be the recoil velocity after gun has fired

patulong naman​


Sagot :

Answer:

The answer is -0.375 m/s

Explanation:

Given:

Mass of the gun=1 kg

Mass of the bullet=2.5g

Initial velocity of the gun=0 (at rest)

Initial velocity of the bullet=0 (before collision)

Final velocity of the gun=(X)

Final velocity of the bullet= 150m/s

Solution

(1 kg)(0) + (2.5 g)(0)=(1 kg)(X) + (2.5g)(150m/s)

Convert first the kilograms to grams

1 kg=1000 grams

So,

= (1000)(0) + (2.5)(0) = (1000)(x) + (2.5)(150)

= 0+0 = 1000x+375

= -375= 1000x

=(-375/1000)= x

x = -0.375

Final answer : -0.375 m/s

(sana makatulong, hindi ko ni round off kase I'm not sure if pwede yon sa physics pero base sa modules ko, exact velocity lang ang nakalagay, hindi na ni round off)