IDNStudy.com, ang iyong destinasyon para sa mabilis at kaugnay na mga sagot. Ang aming komunidad ay narito upang magbigay ng detalyadong sagot sa lahat ng iyong mga katanungan.

The system gains 2500 J of heat in addition to the work done on the system by the surrounding which is 2000 J. Calculate the change in the internal energy of the system.


Sagot :

Answer:-

  • Internal energy before work done=E_1=2000J
  • Internal energy after work done=E_2=2500J
  • Change in internal energy=E_net

we know

[tex]\boxed{\sf E_{net}=E_2-E_1}[/tex]

[tex]\\ \sf\longmapsto E_{net}=2500-2000[/tex]

[tex]\\ \sf\longmapsto E_{net}=500J[/tex]