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DIRECTION: Solve the problem showing a complete solution.
1. Two ice skaters stand together. They ''push off'' and travel directly away each other, the boy with a velocity of +0.50 m/s and the girl with velocity of -0.65 m/s. If the mass of the boy is 60.0kg. What is the girl's mass?
Solution: The momentum of the boy-girl system is conserved. There is no change in the momentum of the system before and after the push off.
Total Initial momentum = Total Final Momentum
0 = Pboy + Pgirl
-Pboy = Pgirl
-(mv)boy = (mv)girl
-30.0 kg m/s = (Mgirl) - 0.65 m/s
46kg =(Mgirl)
2. A 3.0 x 10² g cart moves on an air track at 1.2 m/s. it collides and sticks to another cart of mass 5.0 x 10² g, which was stationary before collision, What is the velocity of the combined cart after collision?
Mass Velocity (before collision)
Cart 1 = 0.30kg 1.2 m/s
Cart 2 = 0.50kg 0
Total momentum Before collision = Total momentum after collision
( Pcart1 + Pcart2) before = (Pcart1 + Pcart2) After
(m₁ + v₁) before + 0 = ( m₁ + m₂) v after
0.36 kg m/s = 0.80 kg v after
0.45 m/s = V after
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