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Juan's age on his birthday in 1989 is equal to the sum of the digits of the year 19xy in which he was born. If x and y satisfy the equation x-y-6=0, find the age of Juan in 1990.

Sagot :

Brainlymomshieidn

Problems Involving Algebraic Expressions

To solve this problem, we need to represent the unknown using any variable. Form the algebraic expression using the given. Make sure to analyze the problem clearly so that the correct operation will be used. Look for clues example the word sum which means addition. Check the answers obtained by using the algebraic expressions formed.

Answer:

17 years old

Solutions:

Let: x - be Juan's age in 1989

then,

x + 1 - will be Juan's age in 1990

Given: 19xy

           x - y - 6 = 0

Solve for x in terms of y.

x - y - 6 = 0

x - y - 6 + 6 = 0 + 6

x - y = 6

x = 6 + y

Substitute x = 6 + y on the equation.

x - y - 6 = 0

(6 + y) - y - 6 + 6 = 0 + 6

6 + y - y - 6 + 6 = 6

y - y = 6 - 6

y = 0

Solve for x.

x - y - 6 = 0

x - 0 - 6 + 6 = 0 + 6

x = 6

Place the values of x and y in 19xy.

1960

Add the digits of year 1960.

1 + 9 + 6 + 0 = 16

Therefore, Juan's age in 1989 is 16.

Find his age in 1990.

x + 1 = Juan's age in 1990

16 + 1 = Juan's age in 1990

17 = Juan's age in 1990

Therefore, Juan is 17 years old in 1990.

How to solve problems involving algebraic expressions: https://brainly.ph/question/9990249

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